If a certain battery supplies 1.0×108 electrons per second to the negative terminal and the battery contains 7.00 moles of electrolytic solution (which means the solution contains 7.00 moles of hso4), what fraction of the solution undergoes a chemical reaction each second

The answer to the question is

Fraction of solution in reaction = 1.18 × 10⁻¹⁷

Explanation:

The reaction is as follows

H₂SO₄ ⇆ H⁺ + HSO₄⁻

Negative electrode

Pb +  HSO₄⁻ ⇆ PbSO₄ + H⁺ + 2e⁻

That is one mole of H₂SO₄ produces 2 moles of electtrons to the negative electrode

number of electrons in one mole of electrons = Avogadro's number =6.02×10²³

Therefore 7 moles will produce 14 moles of electtrons

Total number of electrons = 14 × 6.02×10²³ = 8.428×10²⁴ electrons

Fraction of electron produced = Fraction of solution in chemical reaction

= 1.0×10⁸÷8.428×10²⁴ = 1.18 × 10⁻¹⁷

Fraction of solution in reaction = 1.18 × 10⁻¹⁷