Talia took the bus from her home to the bank and then walked back to her home along the same route. the round trip took 0.9 hours total. the bus traveled at an average speed of 40 km/h and she walked at an average speed of 5 km/h. use the table to complete these statements. the rate of trip 2 is km/h. the time of trip 1 is hours.

It is 5 then 0.9-x on E2020

Step-by-step explanation:

The rate of trip 2 is 5 km/h

The time of trip 1 is 0.9-x hours

The rate of trip 2 is 5 km/h

The time of trip 1 is 0.9-x

Step-by-step explanation:

The rate of trip 2 is 5 km/h because it tells you she walked at an avg speed of 5 km/h.

The time of trip 1 is 0.9-x. It's because the time in trip 2 is x, and it says the total is 0.9. So just subtract 0.9-x.

Also I took the test on edge and attached a pic.

Trip 1 40; 0.9-x; 40(0.9-x)

Trip 2: 5; x;5x

Explanation:

Since this is a rate problem.

The first trip has a rate of 40km/h

Speed = distance/time

The second trip has a rate of 5km/h

If the time it took Talia to walk is x hours

And she spent a total of 0.9 hours on the journey. So she spent 0.9-x hours on the bus

Distance for the first trip = speed × time

Distance = 40× (0.9-x)= 40(0.9-x)

Distance for the second trip = 5× x= 5x

Just set up the equation and solve for x, that is the time.

40(0.9-x) = 5x
36 = 45x
x = 36/45
 x = 0.8

It took Talia 0.8 hours (48 minutes) to walk home. 

The bus traveled at an average speed of 40 km/h and she - 2385764. ... bus from her home to the bank and then walked back to her home along the same route. ... To determine the time, x, that it took Talia towalk home, she used the equation 40(0.9 – x) = 5x. 1 ... Therefore, it took Talia 0.8 hour to walk home or 48 minutes

Trip 1 40 0.9-x. 40(0.9-x)
Trip 2 5. x. 5x

5 and then 0.9-x

Step-by-step explanation: