Mathematics, 21.06.2019 19:00 ltawiah8393

Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?

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Answer from: floydsidney1119

Hey there!

For the first step you'll have to find your common multiples of each of the factors that you may have Then, look for your variables in the terms/ between each of the factors Once when you do that, factor it (like the pairs that factor out)

Now, let's solve your particular equation now

$\bold{Factor}$ → $\bold{4x^3+x^2-8x-2}$ $\bold{Pair}$ $\bold{off:}$ $\bold{-8x}$ and also, $\bold{4x^3}$ → $\bold{(4x+1)(x^2-2)}$ Then, find your common factors, which is: $\bold{4x}$ There's more steps to solve this, but it will take a while to solve itSo, $\boxed{\boxed{\bold{ (4x+1)(x^2-2)}}}$

Good luck on your assignment and enjoy your day!

~ $\bold{LoveYourselfFirst:)}$

Answer from: yayamcneal05

x^2 (4x + 1) - 2x ( 4x + 1)

Step-by-step explanation:

Check Via multiplication

x^2(4x) = 4x^3.

x^2(1) = x^2.

That gives us the 4x^3 + x^2.

-2(4x) = -8x.

-2(1) = -2.

that gives us the 8x - 2

Therefore, x^2 (4x + 1) - 2x ( 4x + 1) = 4x^3 + x^2 - 8x - 2

Hope this helps. Have a great day!

~a.w.e.s.w.a.n♥

Answer from: EricaLSH7624

4x^3 + x^2 – 8x – 2
= (4x^3 + x^2) – (8x + 2)
= x^2 (4x + 1) - 2(4x + 1)
= (x^2 - 2)(4x +1)

hope that helps

Answer from: narwalmaster2001

(4x + 1)(x² - 2)

Step-by-step explanation:

Given

4x³ + x² - 8x - 2 ( factor the first/second and third/fourth terms )

= x²(4x + 1) - 2(4x + 1) ← factor out (4x + 1) from each term

= (4x + 1)(x² - 2)

Answer from: cass9980

(4x+1)(x²-2)

Step-by-step explanation:

one way to determine the factors of 4x^3 + x^2 - 8x - 2 by grouping:

x²(4x+1)-2(4x+1)

(4x+1)(x²-2)

Answer from: alicia186

(x^2-2)(4x+1)

Step-by-step explanation:

4x^3 + x^2 - 8x - 2

Group:

(4x^3 + x^2)+( - 8x - 2)

Factor out as much as possible: (The GCF)

x^2(4x+1)-2(4x+1)

Regroup:

(x^2-2)(4x+1)

Answer from: justice808

A) x2(4x + 1) – 2(4x + 1)

Step-by-step explanation:

Edg

Answer from: elrancho

Step-by-step explanation:

Answer from: andy2461

Remember that to factoring by grouping, we should split the expression into tow pairs that have something in common. The idea is that after factoring each pair, we get a binomial common factor. Is worth pointing out that you can pair factors in more than one way.

Let's check how to determine the factors of our expression by grouping:

Step 1. Look for common multiples between the terms.

Notice that 4 and 8 are multiples of 2, 8 is a multiple of 4, and all of them are multiples of 1, so we are going to try more than one pairing combination.

Step 2. Look for common factors between the variables.

Usually, we want to pair variables with higher exponents so when we factor each pair, we end up with another common factor in binomial form.

Step 3. Factor each pair; if you end with another binomial common factor, you nailed it. If not, try again.

Les't apply our steps to our expression 4x^3+x^2-8x-2

Applying step 1, we are pairing 4x^3 and -8x . Remember to pair the remaining factors as well.

(4x^3-8x)+(x^2-2)

The common factor in the first pair is , so lets factor that out

4x(x^2-2)+(x^2-2)

Look! we have the binomial common factor (x^2-2) . Unfortunately, 4x(x^2-2)+(x^2-2) is not in our given choices, so let's try again:

This time we are going to group the higher variables (step 2) 4x^3 and x^2

4x^3+x^2-8x-2

(4x^3+x^2)+(-8x-2)

The common factor in the first pair is x^2 , and the common factor in the second one is -2, so let's factor out both of them:

(4x^3+x^2)+(-8x-2)

x^2(4x+1)-2(4x+1)

This time, we got option A.

We can conclude that the correct answer is: A) x2(4x + 1) – 2(4x + 1)

Answer from: Nason156

see explanation

Step-by-step explanation:

Given

4x³ + x² - 8x - 2 ( factor the first/second and third/fourth terms )

= x²(4x + 1) - 2(4x + 1) ← first option on list

Finishing the factoring by factoring out (4x + 1) from each term

= (4x + 1)(x² - 2)

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