Arunning track in the shape of an oval is shown. the ends of the track form semicircles. a running track is shown. the left and right edges of the track are identical curves. the top and bottom edges of the track are straight lines. the track has width 56 m and length of one straight edge 130 m. what is the perimeter of the inside of the track? (π = 3.14) 260.00 m 347.92 m 372.00 m 435.84 m

444.44

The answer is D. 435.84 m

I took an FLVS test and got the question right

493.52 m :)

493.52

Step-by-step explanation:

i believe the answer is '324.00

the answer is 444.44

The two ends of the track are semi circles, so we need to calculate the circumference:

Circumference = PI x 56 = 175.84

The two straight  parts are 130 m each:

Total perimeter = 175.84 + 130 + 130 = 435.84 m

The answer is D.

Im not sure but i think its 372.22
if im wrong tell me

P L E A S E   A N S W E R   Q U I C K L Y

O K   I   W  I  L L

P = 2L + (3.14)D
P = 2(150) + (3.14)(46)
P = 300 + 144.44
P = 444.44

T W O   S E M I C I R C L E S  =  O N E   C I R C L E

Y O U   N E E D   TO   F I N D   T H E   C I R C U M F R E N C E                  A N D   T W O   L E N G T H S   T O   S O L V E

Two shapes.. a circle and a rectangle. The width of the rectangle serves as the diameter of the circle.

Length = 140 m ; Width = 68 m

Circumference of a circle = 2 π r
circumference of a cirlce =  2 * 3.14 * (68m/2) = 2 * 3.14 * 34 m = 213.52

length = 2 * 140 m = 280 m

perimeter of the oval = 213.52 m + 280 m = 493.52 m