Peter applied to an accounting firm and a consulting firm. he knows that 30% of similarly qualified applicants receive job offers from the accounting firm, while only 20% of similarly qualified applicants receive job offers from the consulting firm. assume that receiving an offer from one firm is independent of receiving an offer from the other. what is the probability that both firms offer peter a job?
D) The average for the last five years fits with the 30-year average.
Let represent the average temperature for the summers.
According to the given description , we have
Null hypothesis :
Alternative hypothesis :
Since Alternative hypothesis is right-tailed , so the test is a right-tailed test.
Given : ; ; n= 5
Test statistic :
From t-distribution table , the critical value for t at and degree of freedom (n-1=4) is 2.776.
Since the observed t-value (2.13) is less than the critical t-value (2.776), it means we are fail to reject the null hypothesis.
Conclusion: The average for the last five years fits with the 30-year average.
question #1 ~ there are 50 boys
11 was multiplied by 5 so you have to do the same for 10
that American is free!
Explanation: subscribe to coryshyper
Answer with Explanation:
Average in Temperature in last 30 years in the month of July for Eloy and Arizona=90°
Standard Deviation =2.1°
→It means ,temperature of last 30 years of states Eloy and Arizona lie between , 90°-2.1° to 90°+2.1°= 87.9° to 90°.
→→Average of last five Summers, for Eloy and Arizona=92°
Calculating , the reduction ,which is equal to 2.5% from 92
→89.70° lies between ,87.9° to 90°.
So,we can confidently assert that→the two averages are probably same.
Option D: The average for the last five years fits with the 30-year average.
E) we will use t- distribution because is un-known,n<30
the confidence interval is (0.0338,0.0392)
Given sample size is n = 23<30 mortgage institutions
The mean interest rate 'x' = 0.0365
The standard deviation 'S' = 0.0046
the degree of freedom = n-1 = 23-1=22
99% of confidence intervals (from tabulated value).
Confidence interval is
the mean value is lies between in this confidence interval
using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.
He knows that 30÷5 is 6. He then multiplies 6 by 6 to get 36
A is option is the best approach for him to find the answer.
it shows how beautiful America is
and how Americans are free and brave
Given that:prob of purchase = 0.3prob of no purchase = 0.7
prob of at least 7 from 10 will make purchase
= prob(7will buy) + prob(8 will buy) + ..+ prob(10 will buy)
= C(10,7) + C(10,8) + C(10,9) + C(10,10)
So the probability that among ten people who are browsing in the store, at least seven will make a purchase is: 0.0105
Peanuts = 100 - 30 = 70%
Ratio would be: 30/70 = 3/7
In short, Your Answer for this part would be 3/7
b) She can write the ratio, she need to remember that the number of peanuts must be greater than the number of raisins by 7/3.
[ defined by our ratio expression ]
c) It would be: 3/7 = x/42
x = 42/7 * 3
x = 6 * 3
x = 18
In short, Your Answer would be 18
Hope this helps!