Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? check all that apply.

Step-by-step explanation:

As we go from (–2, 2) to  (3, 4), x increases by 5 and y increases by 4.  Thus, the slope of the line through (–2, 2) and (3, 4) is

m = rise / run = 4/5.

Use the slope-intercept form of the equation of a straight line:

y = mx + b becomes 4 = (4/5)(3) + b.  Multiplying all three terms by 5, we eliminate the fraction:  20 = 12 + b.  Thus, b = 8, and the equation of the line through (–2, 2) and (3, 4) is y = (4/5)x + 8.

A line parallel to this one would have the form  y = (4/5)x + b; note that the slopes of these two lines are the same, but the y-intercept, b, would be different if the two lines do not coincide.

Unfortunately, you have not shared the ordered pairs given in this problem statement.  

You could arbitrarily let b = 0.  Then the parallel line has equation

y = (4/5)x; if x = 3, then y = (4/5)(3) = 12/5, and so (3, 12/5) lies on the parallel line.

(-1,1) and (-6,-1)

(1,0) and (6,2)

(3,0) and (8,2)

Step-by-step explanation:

The answers are:

(-1,1) and (-6,-1)

(1,0) and (6,2)

(3,0) and (8,2)

Step-by-step explanation:

I know this because I just answered that and got one wrong.  

(–1, 1) and (–6, –1)

(1, 0) and (6, 2)

(3, 0) and (8, 2)

Step-by-step explanation:

Slope of line having points (x1, y1) and (x2,y2) is given by (y2-y1)/(x2-x1)

Two lines with slope m1 and m2 are parallel if there slopes are equal i.e m1 = m2.

Slope of line  that contains (3, 4) and (–2, 2)

m = (2-4)/(-2-3) = -2/-5 = 2/5

To find if other pair of lines lie on line parallel to  line  that contains (3, 4) and (–2, 2), we need to find slope for other pair of points , if those pairs have slopes as 2/5 then its clear that they lie on line parallel to  line  that contains (3, 4) and (–2, 2) else not.

Lets find slope of all the pairs

(–2, –5) and (–7, –3)

m1 = -3 -(-5)/-7-(-2) = -3+5/-7+2

m1 = 2/-5 = -2/5

as  -2/5 is not equal to 2/5, the mentioned points do not  lie on line parallel to  line  that contains (3, 4) and (–2, 2).

 

(–1, 1) and (–6, –1)

m2 = -1 -1)/-6-(-1) = -2/-6+1

m2 = -2/-5 = 2/5

as  2/5 is  equal to 2/5, the mentioned points do  lie on line parallel to  line  that contains (3, 4) and (–2, 2).

 

(0, 0) and (2, 5)

m3 = 5 -0)/2-0

m3 = 5/2

as   5/2 is not equal to 2/5, the mentioned points do not lie on line parallel to  line  that contains (3, 4) and (–2, 2).

 

(1, 0) and (6, 2)

m4 = 2 -0)/6-1

m4 = 2/5

as  m4

As m4 is  equal to 2/5, the mentioned points do  lie on line parallel to  line  that contains (3, 4) and (–2, 2).

 

(3, 0) and (8, 2)

m5 = 2 -0)/8-3

m5 = 2/5

as  m5 is  equal to 2/5, the mentioned points do  lie on line parallel to  line  that contains (3, 4) and (–2, 2).

Thus, pair of points which lie on  lie on line parallel to  line  that contains (3, 4) and (–2, 2) are

(–1, 1) and (–6, –1)

(1, 0) and (6, 2)

(3, 0) and (8, 2)

-The required ordered pairs are (–1,1) and (–6,–1),(0, 0) and (2, 5)  and (3, 0) and (8, 2).

Explanation:-

We know that parallel lines have equal slopes.

Slope of line that contains (3,4) and (-2,2)=

Given options are:-

Slope of line that contains (–2,–5) and (–7,–3)= Slope of line that contains (–1,1) and (–6,–1) = Slope of line that contains (0, 0) and (2, 5)= Slope of line that contains (1,0) and (6,2) = Slope of line that contains (3, 0) and (8, 2)=

We can see Slope of line contains (–1,1) and (–6,–1), Slope of line that contains (0, 0) and (2, 5) and Slope of line that contains (3, 0) and (8, 2) have same slope as the given line.

Thus the required ordered pairs are (–1,1) and (–6,–1),(0, 0) and (2, 5)  and (3, 0) and (8, 2).

The answer is b,d,e.

The required ordered pairs are (–1,1) and (–6,–1),(0, 0) and (2, 5)  and (3, 0) and (8, 2).

Step-by-step explanation:

We know that parallel lines have equal slopes.

Slope of line that contains (3,4) and (-2,2)=

Given options are:-

Slope of line that contains (–2,–5) and (–7,–3)= Slope of line that contains (–1,1) and (–6,–1) = Slope of line that contains (0, 0) and (2, 5)= Slope of line that contains (1,0) and (6,2) = Slope of line that contains (3, 0) and (8, 2)=

We can see Slope of line contains (–1,1) and (–6,–1), Slope of line that contains (0, 0) and (2, 5) and Slope of line that contains (3, 0) and (8, 2) have same slope as the given line.

Thus the required ordered pairs are (–1,1) and (–6,–1),(0, 0) and (2, 5)  and (3, 0) and (8, 2).

I hope this helped. I am sorry if you get this wrong.

I’m stuck on this as well

The equation of the line containing the points (3, 4) and (-2, 2) is:
 
 Where,
 
 
 
 Substituting values:
 
 
 A parallel line is one that has the same slope:
  
 An ordered pair that passes through this line is (0, 0).
 
 A parallel line is:
 
 an ordered pair that goes through the parallel line is:
 (0, 0)

the original equation?