You own a nonunion company with 93 nonexempt employees. all of these employ- ees pack books into boxes for shipment to customers throughout the united states. because of wide differences in performance, you have decided to try performance appraisal, something never done before. until now, you have given every worker the same size increase. now you want to measure performance and reward the best performers with bigger increases. without any further information, which of the five types of appraisal formats do you think would be most appropriate? justify your answer. do you anticipate any complaints, or other comments, from employees after you implement your new system?
It ees what it ees
It is not what it is
it i what it i
Q2). D (Milk that has been treated with mild heat to eliminate pathogens)
Q3). I believe A, although, could possibly be D (Clarified butter is butter from which water and milk solids have been removed, so that only the butterfat remains)
Q4). C (between 32°F and 45°F)
Q5). A (the room temperature wont effect the cream, unless its extremely hot)
Q6). C (sweetened condensed milk is always sweetened, while evaporated milk is unsweetened)
Q7). A (Cook at a low heat)
Q8). C (Whipping cream isn't fermented)
Q9). D (Cheddar)
Q12). C or D (both cheddar and gouda are hard cheeses)
Q14-17). Didn't understand, I apologise.
Q18). A (curd)
Q19). I believe B (It really depends on the cheese type, some prefer being wrapped in wax paper, others tightly in glad-wrap papers, and then few even sit fine in just an air tight container)
I hope this helped.
The probability that exactly 2 of the next four customers order turkey entries is 6 * 0.0393359 = 0.2360
There are a total of 8+12+10 = 30 entries, 8 of them being turkey. Lets compute the probability that the first 2 customers order turkey entries and the remaining 2 do not.
For the first customer, he has 8 turkey entries out of 30, so the probability for him to pick a turkey entry is 8/30. For the second one there will be 29 entries left, 7 of them being turkey. So the probability that he picks a turkey entry is 7/29. The third one has 28 entries left, 6 of them which are turkey and 22 that are not. The probability that he picks a non turkey entry is 22/28. And for the last one, the probability that he picks a non turkey entry is 21/27. So the probability of this specific event is
8/30*7/29*22/28*21/27 = 0.0393359
Any other event based on a permutation of this event will have equal probability (we are just swapping the order of the numerators when we permute). The total number of permutations is 6, and since each permutation has equal probability, then the probability that exactly 2 of the next four customers order turkey entries is 6 * 0.0393359 = 0.2360
Number of ways to select three ees from seven ees are =
Number of ways to select two mes from five mes are =
For each of the 35 groups of ees 10 groups of mes can be formed. So the total number of groups that can be formed will be 35 x 10 = 350
So there are 350 ways to form such a committee with three ees and two mes from a group of seven ees and five mes.