Achemist 16 drop copper metal from copper chloride solution. the chemist place is 0.50 g of aluminum foil in a solution containing 0.75 g of copper (ii) chloride. a single replacement reaction takes place. which statement explains the maximum amount of copper that the chemist can extract using this reaction?

"Active metals will react with acids in double replacement reactions" is the statement among the following statements that is not true regarding acids. The correct option among all the options that are given in the question is the last option or option "D". I hope that this answer has helped you.

3, 9, 16 are correct! 17 should be b because buffered means that it resists change in pH

Active metals will react with acids in double replacement reactions.

Explanation:

Acids are substances which dissociate in water to give ions.

1. Weak acids are those acids which partially dissociate in water.Most fruits contain weak acids. Lemons contain citric acid, vinegar contains acetic acid.

2. Acids react with bases to form salt and water and are called as neutralization reactions.

3. Concentrated acids containing large amounts of acid are highly corrosive and dilute solutions of acids containing high amounts of water are mildly corrosive.

4. Active metals undergo reaction with acids in single replacement reactions in which metals displace hydrogen from their salt solutions.

A single replacement reaction, sometimes called a single displacement reaction, is a reaction in which one element is substituted for another element in a compound. The starting materials are always pure elements, such as a pure zinc metal or hydrogen gas, plus an aqueous compound.

Explanation:

Brainliest please?

a) saturated with CaCO3, because when maximum solute gets dissolve to form precipitate as when solute is saturated with solvent and then precipitates hence the supernatant is saturated with CaCO3.

Explanation:

In double displacement reaction two ionizable compounds exchange their cation or anion forming an insoluble compound that is precipitate. The supernatant will be the solvent and dissolved solute.

We know that precipitation is formed when solubility of the compound exceeds to that of other.

The solubility occurs when it exceeds the saturation in the solution.

So, the precipitate has overcome the saturation in solvent, the resulting supernatant is saturated with CaCO3 or the solute.

Answer & Explanation:

The replacement of aluminium (Al) by copper (Cu) can be represented by the following chemical equation:

3CuCl2 + 2Al  = 2AlCl3 + 3Cu

We are given 0.50g of Al, and 0.75g of CuCl2

We calculate the maximum amount of copper by assuming one of the reactants (CuCl2 or Al) will be depleted.

Calculations:

The corresponding molecular masses are :

3CuCl2 = 3 (63.546+2*35.457) = 403.38 (1)

2Al = 2*26.9815 = 53.963(2)

2AlCl3 = 2 (26.9815+3*35.457) = 266.705  (we don't need to know this!)

3Cu = 3*63.546 = 190.638(3)

Assuming 0.50g of aluminium will be depleted with unlimited CuCl2, the amount of copper recuperated will be:

M1 = 0.50 *( (3)/(2) ) = 0.50*190.638/53.963 = 1.766 g

If 0.75g of CuCl2 were depleted with unlimited Al, the amount of copper recuperated will be

M2 = 0.75 * ( (3) / (1) ) = 0.75 * 190.638 / 403.38 = 0.354 g  

Therefore CuCl2 is the limiting reagent.

Since we can obtain the maximum amount of copper from the limiting reagent (CuCl2), so the required maximum amount is 0.35 g of copper.

Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.

Explanation:

It is a stichiometry problem.We should write the balance equation of the mentioned chemical reaction:

2Al + 3CuCl₂ → 3Cu + 2AlCl₃.

It is clear that 2.0 moles of Al foil reacts with 3.0 moles of CuCl₂ to produce 3.0 moles of Cu metal and 2.0 moles of AlCl₃.Also, we need to calculate the number of moles of the reported masses of Al foil (0.50 g) and CuCl₂ (0.75 g) using the relation:

n = mass / molar mass

The no. of moles of Al foil = mass / atomic mass = (0.50 g) / (26.98 g/mol) = 0.0185 mol.The no. of moles of CuCl₂ = mass / molar mass = (0.75 g) / (134.45 g/mol) = 5.578 x 10⁻³  mol.From the stichiometry Al foil reacts with CuCl₂ with a ratio of 2:3.

∴ 3.85 x 10⁻³  mol of Al foil reacts completely with 5.578 x 10⁻³  mol of CuCl₂ with (2:3) ratio and CuCl₂ is the limiting reactant while Al foil is in excess.

From the stichiometry 3.0 moles of  CuCl₂ will produce the same no. of moles of copper metal (3.0 moles).So, this reaction will produce 5.578 x 10⁻³ mol of copper metal.Finally, we can calculate the mass of copper produced using:

mass of Cu = no. of moles x Atomic mass of Cu = (5.578 x 10⁻³  mol)(63.546 g/mol) = 0.354459 g ≅ 0.36 g.

So, the answer is:

Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.

idk it but I will guess it's b which might be wrong sorry

Active metals will react with acids in double replacement reactions.

Metals react with acids in single replacement reactions.

Active metals will react with acids in double replacement reactions. 

NH4+ 

increase the volume 
add a catalyst