Which equation represents a circle with a center at (2, –8) and a radius of 11?

(x-h)^2 +(y-k)^2 = r^2 is the equation for a circle centered at (h,k) and radius r

(x-2)^2 +(y- (-8))^2 = 11^2

(x-2)^2 +(y+8)^2 = 11^2

(x-2)^2 +(y+8)^2 = 11^2

(x-2)^2 + (y+8)^2 = 11^2

Step-by-step explanation:

The standard equation of a circle with center at (h,k) and radius r is

(x-h)^2 + (y-k)^2 = r^2.

Filling in the given info, we get:  

(x-2)^2 + (y+8)^2 = 11^2

(x - 2)² + (y + 8)² = 121

Step-by-step explanation:

(x - h)² + (y - k)² = r²

(x - 2)² + (y - -8)² = 11²

(x - 2)² + (y + 8)² = 121

(x - 2)² + (y + 8)² = 121

Step-by-step explanation:

circle: (x – h)² + (y – k)² = r²   (h , k) center        r: radius

h = 2          k = - 8          r = 11

equation: (x - 2)² + (y + 8)² = 121

(x-2)^2 + (y+8)^2 = 121

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-2)^2 + (y- -8)^2 = 11^2

(x-2)^2 + (y+8)^2 = 11^2

(x-2)^2 + (y+8)^2 = 121

2 Nd one

Step-by-step explanation:

Got it right

Step-by-step explanation:

A circle is described by an equation in the following form:

(1)

where:

is the x-coordinate of the centre of the circle

is the y-coordinate of the centre of the circle

r is the radius of the circle

For the circle in this problem, we have:

- The centre is located at (2,-8), so

- The radius is 11, so

Therefore substituting into eq(1) we find the equation of this circle:

So the correct option is option B:

Step-by-step explanation:

This is because if you can see that the, x is being subtracted by 2, making the x-coordinate +2. and the y is being subtracted by 8, making the y coordinate +8.

(2, 8) = Coordinates

And the reason it has a radius of 11 is because the 121 on the other is the product of 11 times 11.

b

Step-by-step explanation:

The  equation of circle is        

Step-by-step explanation:

Given : A circle with a center at (2, –8) and a radius of 11.

To find : Which equation represents a circle?

Solution :

The general equation of the circle is

Where, (h,k)=(2,-8) is the center and r is the radius r=11.

Substitute the value in the formula,

Therefore, The  equation of circle is