Find the values of x and y that satisfy the equation 3x+6i=27+yi

x=9, y=6

Step-by-step explanation:

we have

Equate the Real Numbers

solve for x

Divide by 3 both sides

Equate the  Imaginary Numbers

Simplify

Rewrite

therefore

x=9, y=6

 The required value of x is 3 and that of y is 3.

Step-by-step explanation:  We are given to find the values of x and y that satisfies the following equation :

We know that

That is, the real and parts on both sides of the equation are equal.

From equation (i), we have

Equating the real and imaginary parts on both sides of the above equation, we get

and

Thus, the required value of x is 3 and that of y is 3.

So the value of x=3  and y =3

Step-by-step explanation:

5x + 3i = 15 + yi

To find out x   , set the constant terms  equal to each other and solve for x

5x= 15

Divide by 5 on both sides

x= 3

To find out y   , set the ';i' terms  equal to each other and solve for y

3= y

So the value of x=3  and y =3

The answer to your question is  (4/3, -1)

Step-by-step explanation:

Convert both equations to the same base

        27 = 3 x 3 x 3 = 3³  

          9 = 3 x 3 = 3²

Substitution

Simplify

                                      3x - 6 = 2y                         Equation l

            32 = 2 x 2 x 2 x 2 x 2 = 2⁵

             8 = 2 x 2 x 2 = 2³          

                                   2

Simplify

                                  5y - 3 = -6x                            Equation ll

Equal to zero both equations

                                3x - 2y - 6 = 0                         Equation l

                                6x + 5y - 3 = 0                          Equation ll

Solve by elimination

Multiply equation l by 5 and equation ll by 2

                               15x - 10y - 30 = 0

                               12x + 10y - 6 = 0

                                27x        -36 = 0

Solve for x

                                 27x = 36

                                     x = 36 / 27

Simplify                        x = 4/3

Find the y value

                                6(4/3) + 5y - 3 = 0

                                8 + 5y - 3 = 0

                                      5y = -8 + 3

                                      5y = -5

                                        y = -5/5

                                        y = -1

Solution

                                  (4/3, -1)

x = -2

y = 4

Step-by-step explanation:

Given

Two complex numbers are equal when they have equal real and imaginary parts.

Equate real parts:

Equate imaginary parts:

x = 9 and  y = -3

Step-by-step explanation:

36-yi=4x+3i results to

36=4x and -yi=3i

36/4 = x      -y=3

9 = x           y = -3

x = 9

y = 6

Step-by-step explanation:

3x+6i=27+yi

The real components have to be equal and the imaginary components have to be equal

3x = 27

divide by 3

3x/3 = 27/3

x=9

6i = yi

Divide by i

6 = y

x=9, y=6

Step-by-step explanation:

Step-by-step explanation:

we have

3x+6i=27+yi

Equate the Real Numbers

3x=27

solve for x

Divide by 3 both sides

x=27/3=9

Equate the  Imaginary Numbers

6i=yi

Simplify

6=y

Rewrite

y=6

therefore

x=9, y=6

Y = 3√2 +4

Step-by-step explanation:

y = acosxº + b

Let's look for the values of a and b first.

Let's get values of x and y and solve simultaneously

When x= 0 ,y=10

When x = 120, y= 1

10 =acos0 + b

10 = a +b equation 1

1 = acos120 + b

1= -0.5a + b equation 2

10 = a +b

1= -0.5a + b

10-1= a +0.5a

9 = 1.5a

9/1.5 = a

6 = a

1= -0.5a + b equation 2

1 = -0.5(6) +b

1= -3 + b

1+3 = b

4 =b

So

y = acosxº + b equal to

Y = 6cosx° + 4

So value of y when x= 45 is

Y= 6cos45° +4

Y =6(√2/2) +4

Y = 3√2 +4