You want to divide a square piece of paper into two equivalent triangle if the square measures 20m in each side what will the third side measure

20 √2

It would be a 45 45 90 triangle. So both sides are X (20) and the missing side is X √2 (20 √2).

1) Use the pathagreom theorem; a^2+b^2=c^2
(The hypotenuse is always c. The other two legs can be either a or b.)
*use x for the unknown side*
1. Plug in the measurements
4^2+x^2=8.5^2
2. Solve
16+x^2=72.25
RADICAL(56.25)=> 7.5
The measure of the other side of the triangle (x) is= 7.5 m

2) Draw a square with the measure of 20 cm on each side.
Draw a diagonal line across the square.
(Use the pathagroeam theorem)
We know that the legs are 20, and 20. The hypotenuse is what we are trying to find (x).
1. Plug in the measurements
20^2+20^2=x^2
2. Solve
800= x^2
20 RADICAL(2)=> 28.28
The measure of the other side of the triangle (x) is= 28.3 cm

20 √2 cm or 28.3 cm

Step-by-step explanation:

Folding a paper diagonally will result in two triangles. You know each side of the square piece of paper is 20 cm, so a^2 and b^2 is 20 cm.

Use the formula ‘a^2 + b^2 = c^2’

20^2 + 20^2 = c^2

400 + 400 = 800

√800 = 20 √2 or 28.3 cm

:)