Quadrilateral A(11, -7), B(9, -4), C(11, -1), and D(13, -4) forms a rhombus.
Quadrilateral A(11, -7), B(9, -4), C'(11,1), and D(13, -4) forms a kite.
Rhombus is a quadrilateral whose all sides have equal length.
Kite is a quadrilateral whose four sides can be grouped into two pairs of equal-length sides which are adjacent to each other.
The quadrilateral formed by the vertices A(11, -7), B(9, -4), C(11, -1), and D(13, -4) would result in a rhombus (see figure below) because it had four equal sides.
If C(11,-1) is shifted to the point C'(11,1), it would become a kite (see figure below) because it has two pairs of equal sides.
1. rhombus with non-perpendicular adjacent sides
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Quadrilateral ABCD is a Quadrilateral with four equal sides so either a rhombus or square
Quadrilateral ABC'D is a quadrilateral with two adjacent sides equal so it's a kite shape
(11, -7), B(9, -4), C(11, -1), and D(13, -4).
Let's take out the values of x and y coordinate with the way they are arranged
X = 11,9,11,13
Y = -7,-4,-1,-4
So we observe that distance of the coordinates on either x is 2 units and y is 3 units.
But when the the value was changed to
C′(11, 1), (11, -7), B(9, -4), C′(11, 1), and D(13, -4).
There was difference of 2 unit and 4 unit making the new shape a kite.
The diagram attached explain better
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