Aquadrilateral has vertices a(11, -7), b(9, -4), c(11, -1), and d(13, -4). quadrilateral abcd is a . if the vertex c(11, -1) were shifted to the point c′(11, 1), quadrilateral abc′d would be a .

Quadrilateral A(11, -7), B(9, -4), C(11, -1), and D(13, -4) forms a rhombus.

Quadrilateral A(11, -7), B(9, -4), C'(11,1), and D(13, -4) forms a kite.

Step-by-step explanation:

Rhombus is a quadrilateral whose all sides have equal length.

Kite is a quadrilateral whose four sides can be grouped into two pairs of equal-length sides which are adjacent to each other.

The quadrilateral formed by the vertices A(11, -7), B(9, -4), C(11, -1), and D(13, -4) would result in a rhombus (see figure below) because it had four equal sides.

If C(11,-1) is shifted to the point C'(11,1), it would become a kite (see figure below) because it has two pairs of equal sides.

1. rhombus with non-perpendicular adjacent sides

2. kite

Step-by-step explanation:

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Step-by-step explanation:

Quadrilateral ABCD is a Quadrilateral with four equal sides so either a rhombus or square

But

Quadrilateral ABC'D is a quadrilateral with two adjacent sides equal so it's a kite shape

Step-by-step explanation:

(11, -7), B(9, -4), C(11, -1), and D(13, -4).

Let's take out the values of x and y coordinate with the way they are arranged

X = 11,9,11,13

Y = -7,-4,-1,-4

So we observe that distance of the coordinates on either x is 2 units and y is 3 units.

But when the the value was changed to

C′(11, 1), (11, -7), B(9, -4), C′(11, 1), and D(13, -4).

There was difference of 2 unit and 4 unit making the new shape a kite.

The diagram attached explain better

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