What is the area of this polygon? enter your answer in the box. units² 5-sided polygon on a coordinate plane with vertices g, p, e, s, t. point g is at (negative 3, 4), p is at (2, 4), e is at (4, 2), s is at (2, negative 3), t is at (negative 3, negative 3).

42 sq. un.

Step-by-step explanation:

Consider pentagon GPEST. The area of this pentegon consists of the sum of the area of the rectangle GPST and the area of the triangle PES.

1. The rectangle GPST has sides lengths of 5 un. and 7 un.. Thus, the area of the rectangle GPST is

2. The area of the triangle PES can be calculated as

where h is the height drawn to the side PS. Since PS=7 un., then

Therefore,

42 sq units

Step-by-step explanation:

A diagram is attached.

These points form a pentagon.  This pentagon can be split into a rectangle and a triangle.

The dimensions of the rectangle in the diagram are 5 by 7; this makes an area of A = 5(7) = 35 sq. un.

The dimensions of the triangle in the diagram are a base of 7 and a height of 2.  This makes the area

A = 1/2bh = 1/2(7)(2) = 1/2(14) = 7 sq. un.

This makes the total area

35+7 = 42 sq. units.

16 is the answer to what is the area of this polygon

46 square units

Step-by-step explanation:

First divide the given polygon by joining FS in triangle FNS and rectangle WFSC.

In triangle FNS, construct a line from N (2,4) to its base at (2,-2) and name it point O.

Since it is perpendicular to the base of the triangle therefore, it is the height of the triangle.

Now, by distance formula,

Area of triangle =

Now, in Rectangle WFSC by the distance formula

WF=CS=2 units, FS=WC=9 units

Area of rectangle=

Now, Area of polygon WFNSC= area of triangle +area of rectangle

=27+18=46 square units

  39 units²

Step-by-step explanation:

Quadrilateral VEDR has a width of 5 units and a height of 6 units, so an area of ...

  (5 units)(6 units) = 30 units²

Triangle MVR has a base (VR) of 6 units and a height (M to VR) of 3 units, so an area of ...

  (1/2)(6 units)(3 units) = 9 units²

Then the total area of the polygon MVEDR is ...

  30 units² +9 units² = 39 units²

39 units²

Step-by-step explanation:

The figure is composed of a rectangle VEDR and Δ RMV

Area of rectangle = VE × ED = 5 × 6 = 30 units²

Area of Δ = 0.5 × RV × perpendicular from M to RV

                = 0.5 × 6 × 3 = 9 units²

Thus

Area of polygon = 30 + 9 = 39 units²

45 sq. units

Step-by-step explanation:

We can draw a segment from F to S, splitting this figure into a rectangle and a triangle.

The area of a rectangle is given by the formula A=lw, where l is the length and w is the width.

The width of this figure is the distance of FW; this is 2.  The length of this figure is the distance of WC; this is 9.  This makes the area of the rectangle A=2(9) = 18 sq. units.

The area of a triangle is given by the formula A=1/2(b)(h), where b is the base and h is the height.

The base of the triangle is given by the distance of FS; this is 9.  The height of the triangle is given from N to segment FS; this is 6.  This makes the area of the triangle A=1/2(6)(9) = 27 sq. units.

This makes the total area 18+27 = 45 sq. units.

Step-by-step explanation:

We can divide the polygon into a rectangle and a triangle as shown in the attachment.

The rectangle has dimensions units and units.

The area of the rectangular portion is

square units.

The area of the triangular portion is

square units.

Therefore the area of the polygon is square units.  

Area of polygon = 45 units²

Step-by-step explanation:

Given : The figure attached of the polygon.

To find : What is the area of this polygon?

Solution :

To find the area we divide polygon into two areas by creating a line between F and S.

The two area form are triangle FNS and rectangle FWCS.

In triangle FNS,

Area of triangle is

The Base is unit from F to S is 9 unit (add each block).

The height is unit from N to base is 6 unit.

Area of triangle is

In rectangle FWCS,

Area of rectangle is

The Length is unit from F to S is 9 unit.

The Width is unit from F to W is 2 unit.

Area of rectangle is

Area of polygon = Area of triangle + Area of rectangle

Area of polygon =27+ 18

Area of polygon = 45 units²

From the given graph ,

DEVR is a rectangle

Now we find area of rectange DEVR

Area of rectangle = base * height

In rectangle DEVR , Base = 5 units and height =6 units

Area of the rectangle DEVR = 5 * 6 = 30

Now we find area of triangle MVR

Area of triangle = * base * height

Triangle has base 6 units and height 3 units

Area of triangle MVR = * 6 * 3 = 9

Area of this polygon = Area of the rectangle DEVR + area of triangle MVR

= 30 + 9 = 39 square units