Given that a triangle ABC is rotated 100 degrees counterclockwise about a point P. New triangle formed is Triangle A'B'C'.
A rotation is a transformation in which the object is rotated about a fixed point. The direction of rotation can be clockwise or anticlockwise. The fixed point in which the rotation takes place is called the center of rotation.
Here fixed point is P and angle is 100 degrees
The property of rotation is rotation is a transformation of transforming a geometric figure to a similar figure.
In other words, by rotation here ABC will be similar to A'B'C'
Hence angles of ABC will remain equal to angles of A'B'C' in that order.
So m/_ C'A'B'=m /_CAB
A triangle ABC is rotated counterclockwise (about a point P) by an angle = 100° to create a new triangle A'B'C'.
After rotation points A,B and C will overlap A', B' and C' respectively but angles A, B and C of triangle ABC will remain unchanged.
Therefore, ∠C'A'B' ≅ ∠CAB ≅ 70°
Option C will be the answer.