The cost of two tables and three chairs is $705. if the table costs $40 more than the chair, find the cost of the table and the chair

the cost of the table is

the cost of the chair is

Step-by-step explanation:

Let

x-----> the cost of the table

y----> the cost of the chair

we know that

-----> equation A

-----> equation B

substitute equation B in equation A

Find the value of x

 ---->

Let the cost of chair =x
then the cost of table=x+40

A/Q
2(x+40)+3x=705
2x+80+3x=705
5x+80=705
5x=625
x=125

cost of one table and two chair=125+40+2×125
=415$

STEP 1: Define x:

Let a chair costs x

The table costs x + 40

STEP 2: Form equation:

2 Tables and 3 chairs cost $705

2(x + 4) + 3x = 705

STEP 3: Solve x:

2(x + 40) + 3x = 705

2x + 80 + 3x = 705

5x + 80 = 705

5x = 625

x = $125

STEP 4: Find the cost of 1 table and 2 chairs:

(125 + 40) + 2(125) = 165 + 250 = $415

The cost of 1 table and 2 chairs is $415

I'm not sure

Step-by-step explanation:

705÷5 = 141

141+40= 181

181+181= 362

705-362=343

343÷3=114

$181 per table

$114 per chair

I'm not sure, I just guessed it. Try to solve it, I'm not sure though.