Ian is in training for a national hot dog eating contest on the 4th of july. on his first day of training, he eats 4 hot dogs. each day, he plans to eat 110% of the number of hot dogs he ate the previous day. write an explicit formula that could be used to find the number of hot dogs ian will eat on any particular day.

 

Step-by-step explanation:

Since, the initial number of hot dogs = 4

According to the question,

The number of hot dogs is increasing by 110% of that of previous day,

Thus, the number of hot dog in first day = 4

Second day = 110 % of 4 = 4.4

Third day = 110% of 4.4 = 4.84

Fourth day = 110% of 4.84 = 5.324

So on.......

Thus, we get a GP,

4, 4.4, 4.84, 5.324 ..........................

That having common ratio, d = 1.1

And, first term, a = 4

Since, the nth term of the GP,

Hence, the required explicit formula of the given situation,

The number of hot dogs on any particular day is given by:

where n represents the nth day.

Step-by-step explanation:

Let represents the number of hot dogs in nth day of his training.

As it is given that  he eats 4 hot dogs on his first day of training that means:

Now it is also given that:

he plans to eat 110% of the number of hot dogs he ate the previous day.

i.e. the recurrence relation is given as:

which could also be written as:

Now:

Hence, the number of hot dogs on any particular day is given by:

where n represents the nth day.

506 students

Step-by-step explanation:

34.55;

Step-by-step explanation:

110% × ? = 38

? =

38 ÷ 110% =

38 ÷ (110 ÷ 100) =

(100 × 38) ÷ 110 =

3,800 ÷ 110 ≈

34.545454545455 ≈

34.55;

I think this question needs more information.

Step-by-step explanation:

to figure out 110% of the students who walk, we need to know how many students walked to school.

Its probaly: B, D, and E

Step-by-step 110% × 38 =

(110 ÷ 100) × 38 =

(110 × 38) ÷ 100 =

4,180 ÷ 100 =

41.8;

A) 2277 =  110% of number in 2013

b) Number in 2013 = 90% of year before, 2012

2277 = 110% of Number in 2103

2277 = (110/100) * Number in 2013

2277 * 100/110   =  Number in 2013

2070 =   Number in 2013

Number in 2013 is = 2070

b) Number in 2013 = 90% of year before, 2012

     2070  =  (90/100) * Number in 2012

     2070 * 100/90  =  Number in 2012

     2300 =    Number in 2012

Hence number in 2012 =  2300 student athletes.

In 2014 , 2277 was 110% of 2013.

Number in 2013 = 90% of the year before (2012)

Let the number in 2013 be x. From the first statement,

2277 = 110% of x

2277 = (110/100)x

2277 = 1.10x

x = 2277/1.1 = 2070

Number in 2013 is 2070

Number in 2013 = 90% Number in 2012

2070 = (90/100) * Number in 2012

2070 = 0.90 * Number in 2012

2070 / 0.90    = Number in 2012

2300  = Number in 2012

Number in 2012  =  2300

In 2014, 2,277 was 110% of 2013.

Number in 2013=90% of the year before (2012)

Let the number in 2013 be x. From the first statement,

2,277 = 110% of x

2,277 = (110/100)x

2,277 = 1.10x

x = 2,277/1.1 = 2,070

Number in 2013 is 2,070

Number in 2013 = 90% Number in 2012

2,070 = (90/100) * Number in 2012

2,070 = 0.90 * Number in 2012

2, 070 / 0.90 = Number in 2012

2,300 = Number in 2012

Number in 2012 = 2,300