Janet is rolling a number cube with the numbers one through six she record the numbers after each row if she rolls of keep 48 times how many times should she expect to roll a 4

10 times bc 1/6= x/60

20 times                    But if you wanna see how I got it, there you go

Step-by-step explanation:

We are given a cube that has s 6 faces that are numbered from 1 through 6. She  expect to roll a number that is greater than 4 . A number greater than 4 of dice = 5 or 6 Probability of getting 5  = Favorable event ={5}=1 Total events ={1,2,3,4,5,6}=6 So probability of getting 5  = Probability of getting 6  = Favorable event ={6}=1 Total events ={1,2,3,4,5,6}=6 So probability of getting 6  = Thus the probability of getting 5 or 6 = = = Since  She plans on rolling the number cube 60 times So,she expect to roll a number that is greater than 4= =20 Hence she should expect 20 times to roll a number that is greater than 4

20 times

Step-by-step explanation:

We are given a cube that has s 6 faces that are numbered from 1 through 6.

She  expect to roll a number that is greater than 4 .

A number greater than 4 of dice = 5 or 6

Probability of getting 5  =

Favorable event ={5}=1

Total events ={1,2,3,4,5,6}=6

So probability of getting 5  =

Probability of getting 6  =

Favorable event ={6}=1

Total events ={1,2,3,4,5,6}=6

So probability of getting 6  =

Thus the probability of getting 5 or 6 =

                                                              =

                                                               =

Since  She plans on rolling the number cube 60 times

So,she expect to roll a number that is greater than 4=  

                                                                                             =20

Hence she should expect 20 times to roll a number that is greater than 4

Greater than 4 means either 5 OR 6, that means the probability of getting 5 or 6 is 2/6 ==>1/3

Theoretically she needs 3 Rolls to get a number greater than 4 

I believe the answer is about 10 

Is there more to this question because it doesn’t make sense

Number of possible outcome = 6

Number of outcomes greater than 4 = 2 
(face with number 5 + face with number 6)

P(greater than 4) = 2/6 = 1/3

If she rolled it 60 times, 
P(she will get greater than 4) = 1/3 x 60 = 20 

20 times

On a standard die the probability would be 2/6

Only 2/6 times would you expect to roll a number greater than 4 at any given roll

She should expect to roll a three 10 times