Which steps could be part of the process in algebraically solving the system of equations, y+5x=x^2+10 and y=4x-10

0 = x2 - 9x + 20

Step-by-step explanation:

y + 5x = x² + 10     Simplify this equation

  - 5x   - 5x

y = x² - 5x + 10

Set both equations equal to each other since they both equal y

x² - 5x + 10 = 4x - 10

    -4x           - 4x

x² - 9x + 10 = -10

         + 10   + 10

x² - 9x + 20 = 0

If this answer is correct, please make me Brainliest!

0+x^2-9x+20

One x-value of a solution to the system is 4

Step-by-step explanation:

Step-by-step explanation:

3. x= 3x − 5y, y = x − 2y+ t2, x(0) = −1, y(0) = 0, t = 1. 4. x = x + 2y+ cost, y = 5x − 2y, x(0) = 0, y(0) = 1, t = 1. 5. x = x2 − y, y = x + y, x(0) = −1, y(0) = 0, t = 1. 6. x = xy ...

That would be :

 4x – 10 = x2 – 5x + 10  ( y = 4x - 10 is substitute for y)

 PROOF:        y + 5x = x² + 10

                     (4x - 10) + 5x = x² + 10

                      4x - 10  =  x² -5x + 10

    0 = x2 – 9x + 20  (liked terms are grouped and simplified)

PROOF:      4x - 10  =  x² -5x + 10

                   4x = x² -5x + 10 + 10

                    0  = x² -5x -4x + 20

                    0  = x² - 9x + 20

Solving:

             x² - 9x + 20 = 0 

             x² - 5x - 4x + 20 = 0

             (x - 5) (x - 4)  = 0

          ⇒ x = 4  (as question says) OR x = 5

Step-by-step explanation:

hope this helps

There are 5 steps. The solution is (5/4,5)

Step-by-step explanation:

1. In the y+5x=x+10 equation, subtract 5x from both sides to get y=-4x+10.

2. Set y=-4x+10 and y=4x equal to each other to get -4x+10=4x

3. Add 4x to both sides, which leaves you with 10=8x

4.Divide both sides by 8 to get x=10/8 or 5/4 when you simplify

5. Plug 5/4 into the y=4x equation and multiply 5/4 by 4/1, which leaves you with 20/4, or 5.

So the solution to this problem is (5/4,5). If you graph these two equations, you will get the same solution.

IT'S meep  4x – 10 = x2 – 5x + 10  ( y = 4x - 10 is substitute for y)

 PROOF:        y + 5x = x² + 10
                      (4x - 10) + 5x = x² + 10
                       4x - 10  =  x² -5x + 10
     
    
0 = x2 – 9x + 20  (liked terms are grouped and simplified)

PROOF:      4x - 10  =  x² -5x + 10
                    4x = x² -5x + 10 + 10
                     0  = x² -5x -4x + 20
                     0  = x² - 9x + 20

Solving:
              x² - 9x + 20 = 0 

              x² - 5x - 4x + 20 = 0

              (x - 5) (x - 4)  = 0

           ⇒ x = 4  (as question says) OR x = 5

That would be :
 4x – 10 = x2 – 5x + 10  ( y = 4x - 10 is substitute for y)

 PROOF:        y + 5x = x² + 10
                      (4x - 10) + 5x = x² + 10
                       4x - 10  =  x² -5x + 10
     
    
0 = x2 – 9x + 20  (liked terms are grouped and simplified)

PROOF:      4x - 10  =  x² -5x + 10
                    4x = x² -5x + 10 + 10
                     0  = x² -5x -4x + 20
                     0  = x² - 9x + 20

Solving:
              x² - 9x + 20 = 0 

              x² - 5x - 4x + 20 = 0

              (x - 5) (x - 4)  = 0

           ⇒ x = 4  (as question says) OR x = 5