The easiest way to solve this question is to write out both equations in the form y = mx + c, where m is the gradient and c is the y-intercept.
a) Thus, if we start with 9x - 10y = 21, then we get:
9x - 10y = 21
(9/10)x - y = 21/10 (Divide both sides by 10)
(9/10)x = y + 21/10 (Add y to both sides)
(9/10)x - 21/10 = y (Subtract 21/10 from both sides)
Thus, our first equation may be written as y = (9/10)x - 21/10
b) Now if we take the second equation, (3/2)x - (5/3)y = 7/2, we can follow the same process to get:
(3/2)x - (5/3)y = 7/2
(9/10)x - y = 21/10 (Multiply each side by 3/5)
(9/10)x = y + 21/10 (Add y to each side)
(9/10)x - 21/10 = y (Subtract 21/10 both sides)
Thus, the second equation may be written as y = (9/10)x - 21/10.
Now you might have already realised this but the two equations are actually exactly the same; if they are the same line then they are said to be coincident.
Note that if the two lines are parallel, then their gradients (m) would be the same, but the y-intercepts (c) would be different (eg. y = 2x + 3 and y = 2x + 4 are parallel).
If they just intersect at a point, then the gradients of the lines would be different, but the y-intercepts could be the same or different (eg. y = 4x + 2 and y = 9x + 2 intersect at one point).
For them to be coincident however, both the gradient and y-intercept must be the same as only then would they be the same line.
Eq 1 :9x-10y-21=0
Eq 2 : 3/2x -5/2y -7/2=0
a1/a2 = 9/9=1
b1/b2 =-10/-10 =1
c1/c2 =-21/-21 =1
These lines are coincident
The lines are coincident
if a was wrong then it has to be b it cant be c either because not all the y intercepts are the same!
ok now , i would like brainlest plz
use that smart brain