The equation tells you xy = k. Substituting the given values, you get ...
7·3 = k
21 = k
The given inverse variation equation is x.y = k, where k is the constant of proportionality.
Given: x = 7 and y = 3.
We need to find the constant variation, k.
To find the constant variation, k, plug in x = 7 and y = 3 in the given equation and simplify.
k = 7*3
k = 21.
Therefore, the constant of variation k = 21.
Answer is D) 21.
Step-by-step explanation: We are given the inverse variation equation xy = k
We need to find the value of the constant of variation, k for given values x = -2 and y=5.
In order to find the value of the constant of variation, k we need to plug the values of x and y in given inverse variation equation xy = k and solve for k.
Plugging x=-2 and y =5, we get
xy = k => (-2) (5) = k.
On multiplying -2 and 5, we get -10.
Therefore, k = -10.Therefore, the constant of variation k value is -10.
Given: The inverse variation equation is given by :-
To find : The constant of variation, k, when x=-2 and y=5
Substitute the given values of x and y in the given inverse equation , we get
Hence, the value of constant of variation = -10
Option D) 6
What is the constant of variation: k=?
when x=-3 and y=-2
Replacing the knwon values in the given equation:
xy=k; x=-3, y=-2
Multiplying the values:
xy = k
(-2)(5) = k
-10 = k
k=xy x=7 y=3
k=7 x 3
Given the equation for inverse variation
xy = k
We know x=-3 and y = -2
Substituting these values in
(-3) (-2) = k
We are asked to find the constant of variation (k) for the inverse variation equation using formula .
To find the constant of variation we will substitute and in our given formula.
Therefore, the constant of variation of our given inverse equation is 6.
The constant of variation is 6.
The inverse variation equation is:
We want to find the constant of variation, when x=-3 and y=-2.
We substitute the values for x and y to get,
Multiply out the left hand keeping in mind that negative times negative yields a positive result.
This implies that;
Hence the constant of variation is 6.