Drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. match each graph with the function it represents

-----> Graph C

-----> Graph A

-----> Graph B

-----> Graph D

-----> Graph E

Step-by-step explanation:

we have

case a)

Find the domain

we know that

The radicand must be greater than or equal to zero

so

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval ----->  [0,∞)

All real numbers greater than or equal to 0

case b)

Find the domain

we know that

The radicand must be greater than or equal to zero

so

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval ----->  [0,∞)

All real numbers greater than or equal to 0

case c)

Find the domain

we know that

The radicand must be greater than or equal to zero

so

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval ----->  [-1,∞)

All real numbers greater than or equal to -1

case d)

Find the domain

we know that

The radicand must be greater than or equal to zero

so

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval ----->  (-∞,0]

All real numbers less than or equal to 0

case e)

Find the domain

we know that

The radicand must be greater than or equal to zero

so

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval ----->  (-∞,0]

All real numbers less than or equal to 0

Graph A → y=√x.

Graph B → y=(√x) - 1.

Graph C → y=√(x-1).

Graph D → y= -√x.

Graph E → y= -√(x-1)

Step-by-step explanation:

The graph 'A' intercepts the y-axis at (0, 0). Therefore it belongs to the function y=√x.

The graph 'D' is exactly the same graph 'A' but reflected across the x-axis. Therefore, it belongs to the function y=-√x.

The function 'C' is exactly the same function y=√x but translated one unit to the right, therefore, the solution function is y=√(x-1)

The graph 'E' is exactly the same graph 'C' but reflected across the x-axis, therefore the function is: y= -√(x-1)

In the options you have two times the function y=√x. I assume that's a mistake. The graph 'B' corresponds to y = (√x) - 1

Part 1) -----> Graph C

Part 2) ----> Graph D

Part 3) -----> Graph A

Part 4) ---> Graph E

Step-by-step explanation:

Part 1) we have

Find the domain of the function

The radicand must be positive

so

Solve for x

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

so

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph C

Part 2) we have

Find the domain of the function

The radicand must be positive

so

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

so

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph D

Part 3) we have

Find the domain of the function

The radicand must be positive

so

Solve for x

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

so

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph A

Part 4) we have

Find the domain of the function

The radicand must be positive

so

Solve for x

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

so

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph E