What is the interquartile range of this data set? 2, 5, 9, 11, 18, 30, 42, 48, 55, 73, 81

I believe it is 63 although i may be doing the wrong formula. but as far as i can tell thats right.

Step-by-step explanation:

Explanation:

Interquartile range is the difference between the third and the first quartile of a data set.

It is designated by IQR = Q₃ - Q₁.

Then, you must determine first quartile, Q₁, and third quartile, Q₃.

To determine the quartiles you must order the numbers in the data set. They already are ordered.

Then, separate them in two equal parts. When the amount of data in the set is odd, the middle number is the median and it separates the data set into two equal parts:

[ 2, 5, 9, 11, 18 ] 30 [ 42, 55, 58, 73, 81 ]

                          ↑

                       median

The first quartile, Q₁, is the median of the first half of data. This is the median of [ 2, 5, 9, 11, 18 ]. The median is the value of the middle so it is 9.

The third quartile, Q₃, is the median of the second half of data. This is the median of [ 42, 55, 58, 73, 81 ]. The median, again, is the middle, so it is 58.

And, IQR = Q₃ - Q₁ = 58 - 9 = 49.

49

Step-by-step explanation: Apex said so

46

Step-by-step explanation:

55-9=46

2=min

9=Lq

30=median

55= Uq

81= max

46

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

The data must be in ascending order which it is.

First find the median which is the middle value of the data set

2, 5, 9, 11, 18, 30, 42, 48, 55, 73, 81

                        ↑ median = 30

The upper and lower quartiles are positioned at the middle of the data to the right and left of the median.

2, 5, 9, 11, 18, 30, 42, 48, 55, 73, 81

        ↑                                 ↑

upper quartile = 55 and lower quartile = 9

Interquartile range = 55 - 9 = 46

49

Step-by-step explanation:

If so  the inter quartile range = 58 - 9 = 49

79

Step-by-step explanation:

To find the interquartile range, subtract the highest value from the lowest value.

The highest value is 81 and the lowest is 2 so you would have to subtract 81 by 2.

81-2=79

First, find the median: 30

Then, find the median of the 2 sides from 30 (Q1 and Q3)

The middle value between 2 and 18 is 9. The middle value between 42 and 81 is 71. Now, just subtract 71-9.

The IQR is 62 :)

I believe the answer is 62.

Step-by-step explanation:

Hope my answer has helped you!

I think it's 49 I'm sry if I'm wrong hope you luck

Step-by-step explanation: