Three consecutive integers have a sum of –21. which equation can be used to find the value of the three numbers?
x+x+x=-21
x+2x+3x=-21
x+(x+1)+(x+2)=-21
x+(x+2)+(x+4)=-21

The third one, x+(x+1)+(x+2)=-21 because x, x+1 and x+2 are three consecutive numbers.

the third one

Step-by-step explanation:

i took the test

c. x+(x+1)+(x+2)= -21

Step-by-step explanation:

Consecutive integers are in a row, like 1,2,3

Let x =the first integer

The next integer is 1 ahead of it

x+1  = next integer

Add 1 to move to the 3rd integer

x+1+1 = x+2

x+2 = the 3rd integer

Add the 3 integers

x+(x+1)+(x+2) = -21

Maybe C x+(x+1)+(x+2)=-21

Almost positive thats the right answear

The equation which can be used to find the value of numbers

(x) + (x + 1) + (x + 2) = - 21

Step-by-step explanation:

Let the first no. is =  x

Second number = x + 1

Third number = x + 2

The sum of three consecutive numbers = x + x + 1 + x + 2

Given that Three consecutive integers have a sum of –21.

Therefore

(x) + (x + 1) + (x + 2) = - 21

This is the equation which can be used to find the value of numbers.

y + (y+1) + (y+2) = -21

combine like terms

3y +3 = -21

subtract 3 from each side

3y = -24

divide by 3

y = -8

y+1 = -7

y+2 = -6

-8, -7, -6