length of the poster = sqrt (9 ft^2) = 3 ft
length of the cube = cbrt (30 ft^3) = 3.11 ft
Since, the length of the cube is longer compared to the length of the poster then, the poster will lie flat on the cube.
Yes, the posture will be lie flat in the box.
since we have given that
Area of square framed poster = 9 sq. feet
Volume of cube shaped box = 30 cubic feet.
As we know the formula for "volume of cube":
So, Area of cube shaped box would be
Since the cube box is large enough so that the posture will lie flat in the box.
i think No beacuse 9 times 3 is 27 so there is going to be 3 extra
Since the box is cube-shaped, its volume is V = 30 ft^2 = s^3, where s is the length of one side. Then s = ∛30, or approx. 3.11 ft. The length of one side of the 9 ft^2 square poster is √9, or 3 ft. Yes, the 3 ft^2 poster will fit the box, whose bottom area is 3.11 ft^2.
Yes, the poster lie flat in the box.
Consider the provided information.
Talia is packing a moving box. She has a square-framed poster with an area of 9 square feet.
The area of square = (side)²
Thus, the side of the poster frame is:
9 = (side)²
√9 = side
side = 3
Take positive value as side should be a positive number.
The side of the poster frame is 3 feet.
The cube-shaped box has a volume of 30 cubic feet.
Volume of cube = (side)³
Thus, the side of cube-shaped box is:
30 = (side)³
∛30 = side
side ≈ 3.12
The side of cube-shaped box 3.12 feet.
3.12 feet is greater than 3 feet. That means the side of the cube shaped box is greater than side of the poster frame.
Hence, the poster lie flat in the box.