Find the difference of functions s and r shown below. r(x) = –x² + 3x s(x) = 2x + 1 (s – r)(x) =-x^2+3x-2x+1(-x^2+3x)-2x+1(2x+ + 3x)2x+1-x^2+3x

(2x+1) -(-x^2+3x)

Step-by-step explanation:

r(x) = –x² + 3x  

s(x) = 2x + 1

find the difference of (s-r)(x)

(s- r)(x) = s(x) - r(x)

we are given with s(x)  and r(x)

to find the difference we plug both functions

(s- r)(x) = s(x) - r(x)

distribute negative sign inside the parenthesis

(2x+1) -(-x^2+3x) is the way we find difference

(2x + 1) - (–x² + 3x) is difference .

Step-by-step explanation:

Given : r(x) = –x² + 3x  and  s(x) = 2x + 1

To find : Find the difference of functions s and r .

Solution :  We have given that  r(x) = –x² + 3x and s(x) = 2x + 1.

Difference :

(s – r)(x) = s(x) - r(x)

              =(2x + 1) - (–x² + 3x)

              = 2x +1 + x²-3x

             = x²-x +1.

Therefore, (2x + 1) - (–x² + 3x) is difference .

1st box is (2x+1)-(-x^2+3x)    2nd box is x^2 - x + 1

Step-by-step explanation:

took it on edg

Step-by-step explanation:

So we have the two functions:

And we want to find:

This is the same as:

Substitute:

Distribute the -1:

Combine like terms:

And we're done!

So:

Answer & Step-by-step explanation:

In this problem, we are given two functions.

s(x) = 2x + 1

r(x) = -x² + 3x

We are asked to find the difference between s(x) and r(x).

(2x + 1) - (-x² + 3x)

Distribute the negative to the second parentheses.

2x + 1 + x² - 3x

Combine like terms and put the equation in standard form. This means the exponents should be in descending order.

x² - x + 1

So, (s - r)(x) equals x² - x + 1

it's so difficult to do in the mobile

See below.

Step-by-step explanation:

X^2-X+1

Step-by-step explanation:

I understand this question is old, but the only answer provided is incorrect.

This question is off Edgen. Algebra II.

The answer choice for Edg. is the very last option.

(I would provide work but it is not required whatsoever and it's very annoying when you have to read 19 paragraphs just to get an answer)

Hope this helps any future algebra students!