An aircraft performs a maneuver called an "aileron roll." during this maneuver, the plane turns like a screw as it maintains a straight flight path, which sets the wings in circular motion. if it takes it 35 s to complete the circle and the wingspan of the plane is 11 m, what is the acceleration of the wing tip

The acceleration of the wing tip is 0.216 m/s²

Explanation:

Given;

time to complete on circle, t = 36 s

the wingspan of the plane = 14.2 m, this is equal to diameter of the circle, thus radius of the circle, r = ¹/₂ x 14.2 = 7.1 m

distance of a complete circle = circumference of a circle = 2πr

circumference of a circle = 2πr = 2π x 7.1 = 44.6164 m

velocity, v = distance / time

velocity of the wing tip, v = 44.6164 / 36

                                          = 1.239 m/s

Centripetal acceleration of the wing tip = v²/r

                                                                  = (1.239²)/7.1

                                                                  = 0.216 m/s²

Therefore, the acceleration of the wing tip is 0.216 m/s²